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Posted by 70XL
on April 21, 2009, 3:52 pm
71.17.59.179
Some of my numbers need confirmation, but the concept, or approach is what I'd like comments on. A quick recap: I installed new front coils while my engine was out for rebuilding last summer/fall. I liked how the car sat, but the original springs were sacked out and would bottom very easily.
New coils are Moog replacement springs and the front is quite a bit higher than before, headlights don't light the road right now and I odn;t like the negative rake. New front ride height measures 29", old ride height measured ~26", if memory serves. Specs from Moog say the spring has an installed height of 10.50". The free height of the new coils matched the originals and the Ford specs I have indicate a free height of 17.25"
I calculated the relationship of the free height to the installed height, 17.25 / 10.5 = 1.643. If I have a 29" ride height with an installed height of 10.5", what installed height do I need for 26"? (10.5 x 26) / 29 = 9.4". When I multiply the target installed height of 9.4" by the free vs. installed height ratio of 1.643 to get the target free height, 9.4 x 1.643 = 15.44"
My thinking is that if I cut the 17.25" spring to a free height of 15.44" it would result in a ride height of ~26". These are straight rate springs, so I'm assuming a linear relationship. Does this make sense to anyone else? Am I on the right track? Thoughts on how else to approach this to achieve the results I'm looking for. 
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